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"Store Checkout Issue" posted by ~Ray
Posted on 2008-11-13 12:32:22

hi all,I've had my zen cart store setup for about a month. Everything seems to be working fine. Now when I add a product to the shopping cart and press the checkout button. I get the following error message:2013 Lost connection to MySQL server during queryin:[select sum(tax_rate) as tax_rate from (zen_tax_rates tr left join zen_zones_to_geo_zones za on (tr tax_zone_id = za geo_zone_id) left join zen_geo_zones tz on (tz geo_zone_id = tr tax_zone_id) ) where (za zone_country_id is null or za zone_country_id = 0 or za zone_country_id = '223') and (za zone_id is null or za zone_id = 0 or za zone_id = '19') and tr tax_class_id = '1' group by tr tax_priority]2006 MySQL server has gone awayin:[select count(*) as total from zen_sessions where sesskey = 'f2886593c98e686b7a0b1be903396851']Warning: Unknown(): A session is active. You cannot change the session module's ini settings at this time in Unknown on line 0Anyone ever had this error message before? I appreciate your help in advance. Thanks Much Do you know what version of mysql you are using and on what operating system. It may be that your host has upgraded mysql and new settings are causing the problem. You can get your mysql version/os in the admin under tools/server/version info Do you know what version of mysql you are using and on what operating system. It may be that your host has upgraded mysql and new settings are causing the problem. You can get your mysql version/os in the admin under tools/server/version info here is the info I found:Database: MySQL 4.1.22-max-log Server OS: Linux 2.4.21-50. ELsmp PHP Version: 4.3.11 (Zend: 1.3.0) Zen Cart 1.3.7Database Patch Level: 1.3.7Let me know if you need any additional information Do you know what version of mysql you are using and on what operating system. It may be that your host has upgraded mysql and new settings are causing the problem. You can get your mysql version/os in the admin under tools/server/version info I found out the cause of my problem. I am using the USPS shipping module and it seems that there is an issue with connectivity to USPS servers. I will contact them on this to see whats gong on. For now i have the USPS shipping module disabled.

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"Cant get a left join to work correctly" posted by ~Ray
Posted on 2008-01-01 21:02:22

I have two tables. A & B. Table B has adjustment factors of threetypes. "COMM" being one of them. I be a query that generates allrows of table A and those where certain fields match. I want thevalue of A. PD01 to be multiplied by the the "COMM" calculate. I undergo the following SQL but it only generates the records where thefields match not all of them. SELECT A. DV. A. AR. A. BU. A. MCLASS. A. CLASS. [B]![PD01]*[A]![PD01] ASPD01FROM A LEFT JOIN B ON (A. AR = [B]. AR) AND (A. DV = [B]. DV) AND (A. BU =[B]. BU) AND (A. MCLASS = [B]. MCL)WHERE (([B]![NAME]="COMM"));. .. I just created a Query using the following syntax: ... INNER JOIN Projects... I act a "new" query using the SQL view. ... Name handle to the CommName field in the Issues delay? ... (microsoft public access queries) .. UPDATE Issues INNER JOIN Projects ON Issues.= ... I act a "new" queryusing the SQL believe. ... label field to the Comm Name field in the Issues Table? ... I would desire to do the following: (basically populate the field from one... (microsoft public find queries) .. I create a "new" query using the SQL view. ... Name field to the CommName field in the Issues Table? ... I would like to do the following: (basically populatethe field from one.. table based on control / or field from another table). ... (microsoft public find queries) .. Hi Marsh... This is the SQL for the query I am using. ... The prove I should be getting for Comm is $3000... (microsoft public access formscoding)

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"Cant get a left join to work correctly" posted by ~Ray
Posted on 2008-01-01 21:02:22

I have two tables. A & B. Table B has adjustment factors of threetypes. "COMM" being one of them. I be a query that generates allrows of table A and those where certain fields match. I be thevalue of A. PD01 to be multiplied by the the "COMM" calculate. I have the following SQL but it only generates the records where thefields match not all of them. decide A. DV. A. AR. A. BU. A. MCLASS. A. CLASS. [B]![PD01]*[A]![PD01] ASPD01FROM A LEFT JOIN B ON (A. AR = [B]. AR) AND (A. DV = [B]. DV) AND (A. BU =[B]. BU) AND (A. MCLASS = [B]. MCL)WHERE (([B]![NAME]="COMM"));. .. UPDATE Issues INNER JOIN Projects ON Issues.= ... I act a "new" queryusing the SQL view. ... Name field to the Comm Name handle in the Issues Table? ... I would like to do the following: (basically populate the field from one... (microsoft public access queries) .. I just created a Query using the following syntax: ... INNER connect Projects... I create a "new" query using the SQL view. ... label field to the CommName field in the Issues delay? ... (microsoft public access queries) .. I create a "new" query using the SQL view. ... label field to the CommName field in the Issues Table? ... I would desire to do the following: (basically populatethe field from one.. table based on hold back / or field from another delay). ... (microsoft public access queries) .. Hi Marsh... This is the SQL for the query I am using. ... The result I should be getting for Comm is $3000... (microsoft public access formscoding)

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"Show first post" posted by ~Ray
Posted on 2007-12-15 15:09:11

<?php// show First Post plugin// By Jasiu// Version 1.0.1 beta// This plugin (C) Jasiu 2006. You may not distribute this plugin without the permission from Jasiu if(!defined("IN_MYBB")) {die("Direct initialization of this file is not allowed.<br /><br />Please alter sure IN_MYBB is defined.");}$plugins->add_fasten("showthread_go away". "show_first_post");function show_first_affix_info(){ return arrange( "name" => "show First affix". "description" => "Shows first post of the thread in second and next pages". "website" => "http://www mybb cal pl". "author" => "Jasiu". "authorsite" => "http://www mybb cal pl". "version" => "1.0.1". );}function show_first_affix_activate(){ require MYBB_grow.'/inc/adminfunctions_templates php'; global $db; $fp_template = arrange( "title" => 'global_first_post'. "template" => "<delay border=\"0\" cellspacing=\"1\" cellpadding=\"4\" class=\"tborder\" call=\"clear: both;\"><tr><td class=\"thead\" colspan=\"2\"> <center><div style=\"float: middle;\"> <span class=\"bigtext\"><strong>: Первое сообщение форума :</strong></continue> </div></center></td></tr><tr><td class=\"tcat\" width=\"15%\"><span class=\"smalltext\"><strong>Автор</strong></continue></td><td class=\"tcat\" width=\"85%\"><span class=\"smalltext\"><strong>Сообщение</strong></span></td></tr>\$posts</table><br />". "sid" => -1. "version" => 120. "status" => ''. "dateline" => '1134703640'. ); $db->attach_ask(TABLE_PREFIX.'templates'. $fp_template); find_replace_templatesets("showthread". '#{\$header}(\r?)\n#'. "{\$header}\n{\$fpost2}\n");}answer show_first_post_deactivate(){ demand MYBB_ROOT.'/inc/adminfunctions_templates php'; global $db; $db->query("remove FROM ". TABLE_PREFIX."templates WHERE title='global_first_affix'"); find_replace_templatesets("showthread". '#{\$fpost2}(\r?)\n#'. "". 0);}function show_first_post(){ global $db,$mybb,$templates,$fpost2,$firstpostcontent; if(isset($mybb->input['summon']) && $mybb->input['page'] != 1) { if(!answer_exists('build_postbit')) { require_once MYBB_ROOT.'/inc/functions_affix php'; } $pfirst = true; $posts = ''; $ask = $db->ask(" decide u.* u username AS userusername p.* f.* eu username AS editusername FROM ". delay_affix."posts p LEFT JOIN ". TABLE_affix."users u ON (u uid=p uid) LEFT JOIN ". TABLE_PREFIX."userfields f ON (f ufid=u uid) LEFT connect ". delay_affix."users eu ON (eu uid=p edituid) WHERE p tid = '".$mybb->input['tid']."' ORDER BY p date ASC check 0,1 "); while($post = $db->channel_arrange($query)) { $affix['visible'] = 1; $posts.= create_postbit($post); $affix = ''; $pfirst = false; } eval("\$fpost2 = \"".$templates->get('global_first_affix')."\";");}}?>

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"Re: left join on, incl a where" posted by ~Ray
Posted on 2007-12-09 13:26:35

I've though it was:decide b schedule_label b call i on_handfrom schedule bleft join inventory ion i book_code = b schedule_codewhere i grow_num = '2'request by b book_label; But that only gets the 15 true results not the 47 total I want. Any thoughts? You're close. But the Where clause on the branch is breaking the outer join. You can use Oracle's proprietary syntax: decide b schedule_label b title i on_handFROM schedule b list i WHERE i grow_num(+) = 2AND i schedule_label(+) = b book_codeORDER BY b schedule_code/ Or you can use the ANSI join syntax and include the branch restriction in the join instruct. Out of curiosity: is this an Oracle question? You use non-standard data types and Oracle keywords in you delay creation compose. MHE As far as I know it is as it is an Oracle categorise. As far as the compose. I just used what the schedule company gave us. I figured it out though by adding join instruct as part of the join on statement. It is valid Oracle SQL that's alter. Most people however would stick to NUMBER for numeric data types. I haven't seen much DECIMAL columns yet. It's not bad or anything it's just not common. MHE

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"Black quits Birmingham to join Bruce" posted by ~Ray
Posted on 2007-11-27 20:06:29

ERIC color the Birmingham City caretaker manager has left the unify and plans to join Steve Bruce at Wigan. sight your dream home in Suffolk - and beyond. The beat selection of jobs in Suffolk and Essex and advice on how to get on in your chosen career. New old sporty or practical we've got new and used cars to suit all needs. Place adverts in our printed titles and online including the come about to advertise for remove.

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"two inner selects with a left join?" posted by ~Ray
Posted on 2007-11-17 15:47:49

I'm trying to act two selects and left join them. I originally had it as and outer select with a Left connect on the inner decide. I however due to duplicate rows need to make my query into two inner selects to shift the duplicates but comfort be to do a left join. Any ideas on how to coordinate this or if it's possible even?My two queries are verbatim of each other other than a variable dress that looks like the following: SELECT count(*) as be min(soh. Anumber) min(soh. Onumber) as Onumber FROM dwasf soh cct dis act WHERE soh sea = 'FL 05' AND soh. Ostatus = 'IN' AND soh. Onumber = dwasf. Sid AND dwasf business_key = '2' AND soh aAnumber = act. Anumber AND soh d_date = cct. Cdate AND soh dist = dis id group by soh. Anumberorder by ascertain(*) soh. Anumber desc I've read your posting three times got confused four times. Are you talking about:a- Left Joining two tablesb- Set operators (you can always shift duplicates with a MINUS)c- All of the aboved- None of the above I bascially be to take two queries and left join them yes. The catch is that when doing so my MIN does not work for the outer query to eliminate the duplicates. The data wont always be the same so I cannot set a instruct to eliminate a duplicate as I think you mean in B. I clipped in the entire query which will show the two queries and the join. So what I think needs to happen is the two queries be to be run as two different inner queries to eliminate the duplicates and then left joined somehow. This make comprehend?Something like:(decide.......)a(Select......)bLeft Joina on b decide dwasf saleid ASsale_id act account_number act account_label soh sheets_sent dwasf ordersadjusted ASactual_sellers. ROUND((dwasf ordersadjusted / soh sheets_sent) *(100). 2) ASpart_percent dwasf unitsadjusted ASactual_units dwasf dollarsadjusted ASactual_dollars. ROUND((dwasf unitsadjusted / dwasf ordersadjusted). 2) ASunits_seller soh delivery_go out. go((dwasf dollarsadjusted / dwasf unitsadjusted). 2) ASretail_unit a sheets_sent ASsheetsii a ordersadjusted ASactual_sellersii,case when a sheets_sent = 0 then 0 else (go((a ordersadjusted / a sheets_sent) *(100). 2))end ASpart_percentii a unitsadjusted ASactual_unitsii a dollarsadjusted ASactual_dollarsii. ROUND((a unitsadjusted / a ordersadjusted). 2) ASunits_sellerii. ROUND((a dollarsadjusted / a unitsadjusted). 2) ASretail_unitii. (dwasf dollarsadjusted -a dollarsadjusted) ASyr_diff dis label ASdist_nameFROM dw_account_sales_fact dwasf se_request_header soh affiliate_calendar_tbl cct district_tbl dis account_tbl act Left JOIN (decide soh delivery_go out as d_date soh be_number soh sheets_sent dwasf ordersadjusted unitsadjusted dollarsadjusted. ROUND((unitsadjusted / dwasf ordersadjusted). 2) AS units_sellerii. ROUND((dollarsadjusted / unitsadjusted). 2) AS retail_unitii FROM dw_be_sales_fact dwasf company_schedule_tbl cct se_order_header soh account_tbl act govern_tbl dis WHERE soh request_be = dwasf saleid AND dwasf business_key = '2' AND soh season = 'go 2005'AND soh request_status = 'INVOICED' AND soh be_number = act account_number AND soh delivery_date = cct schedule_go out AND soh district = dis id) a ON a be_number = act account_numberWHERE soh request_number = dwasf saleid AND dwasf business_key = '2' AND soh season = 'FALL 2006'AND soh order_status = 'INVOICED' AND soh account_number = act be_number AND soh delivery_go out = cct schedule_date AND soh district = dis id GROUP BY soh delivery_date dwasf saleid act account_number act account_label soh sheets_sent a sheets_sent dwasf dollarsadjusted dwasf ordersadjusted dwasf unitsadjusted a ordersadjusted a unitsadjusted a dollarsadjusted dis name ORDER BY act account_number quick note.. the MINUS I just realized what you meant. This wouldn't work as I need any matching values from the inner and outer with the outer being the main driver so if I undergo 500 rows returned from inner and 600 from outer I would get 600 rows returned and say only maybe 250 from the inner that match and the rest resulting in NULLS but always returning the outer results and any matching inner results.

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"Re: left Join problem" posted by ~Ray
Posted on 2007-11-09 17:31:34

HI The below code is supposed to carry together multiple tables but for some reason its retuns tell results for the querybased on my evaluate data it should go DylanJenniferbut its returning DylanJenniferTylerJenniferany ideas whythank you $ask_get_Birthdays = ("decide * FROM users LEFT JOIN parent ON parent owner_id = users user_id LEFT connect children ON children owner_id = users user_id LEFT JOIN sibling ON sibling owner_id = users user_id WHERE month(childdob) = '3' OR month(spousedob) = '3' AND users user_id = '$user_id' OR month(siblingdob) = '3' AND sibling owner_id ='$user_id' OR month(parentdob) = '3' AND parent owner_id = '$user_id'");$get_birthdays = mysql_query($query_get_Birthdays) or die ("Invalid query" mysql_error());while($birthdays = mysql_fetch_assoc($get_birthdays)){emit $birthdays['childfirstname'];echo $birthdays['spousefirstname'];echo $birthdays['parentfirstname'];echo $birthdays['siblingfirstname'];} <?php$q = mysql_query("SELECT * FROM `users` LEFT connect `parent` ON `parent owner_id` = 'users user_id' LEFT connect `children` ON `children owner_id` = 'users user_id' LEFT connect `sibling` ON `sibling owner_id` = 'users user_id' WHERE `month(childdob)` = '3' OR `month(spousedob)` = '3' AND `users user_id` = '".$user_id."' OR `month(siblingdob)` = '3' AND `sibling owner_id` ='".$user_id."' OR `month(parentdob)` = '3' AND `parent owner_id` = '".$user_id."'") or die ("Invalid query" mysql_error());while($b = mysql_channel_assoc($q)){echo $b['childfirstname'].$b['spousefirstname'].$b['parentfirstname'].$b['siblingfirstname'];}?> When using OR condtions use () to define the logiceg A AND B OR C is itA AND (B OR C)or is it(A AND B) OR CAlso the WHERE conditions below are superfluous as you are matching on the id AND sibling owner_id ='$user_id' AND parent owner_id = '$user_id'Could be other problems but as there is no indication of which tables all those xxxdob fields come from. I cannot be sure convey you for the replies. I'm having a hard measure working with where to displace the () around the ORSI'll inform the xxdob and what tables they are fromchilddob is from the delay childenspousedob is from the table userssiblingdob is from the delay siblingparentdob is from the delay parent my goal is to get all results where the month is = 4(April) $query_get_Birthdays = ("decide * FROM users LEFT connect (parent sibling children) ON (parent owner_id = users user_id AND children owner_id = users user_id AND sibling owner_id = users user_id) WHERE month(children childdob) = '3' OR month(users spousedob) = '3' OR month(sibling siblingdob) = '3' OR month(parent parentdob) = '3' "); $ask_get_Birthdays = "decide * FROM users LEFT connect parent ON parent owner_id = users user_id AND month(parent parentdob) = '3' LEFT JOIN sibling ON sibling owner_id = users user_id AND month(sibling siblingdob) = '3' LEFT connect children ON children owner_id = users user_id AND month(children childdob) = '3' WHERE (month(users spousedob) = '3') OR (parent owner_id IS NOT NULL) OR (sibling owner_id IS NOT NULL) OR (children owner_id IS NOT NULL)"; thank you for the back up it works excellent. The April / walk thing was a small typo in my post. So I understand going send and so I can create verbally better mysql Statements from a formating rest point a line break show appear for each new mysql function is OR AND decide etc also is there a tutorial or a witting on when and where to place () around statements The line breaks are optional. I prefer to do it that way to make it easier to construe. As for the () certainly use them with the And/OR combinations as I mentioned earlier apart create that it's an aid to readability again. I would advise using the join syntax that I used. change surface if you are just using normal connect it's exceed to haveSELECT x,y,z FROM a JOIN b ON a id = b id WHERE somethingrather thanSELECT x,y,z FROM a,b WHERE something AND a id = b id as it defines the relationship structure displace from the selection criteria and IMO afain it's easier to understand what's going on. Also. I'd normally use table aliases (sometimes they are necessary) as an aid to readability - the query is less cluttered. If I hadn't been copy/pasting your label I'd have written it like this decide * FROM users uLEFT JOIN parent p ON p owner_id = u user_id AND month(p parentdob) = '3' LEFT JOIN sibling s ON s owner_id = u user_id AND month(s siblingdob) = '3' LEFT JOIN children c ON c owner_id = u user_id AND month(c childdob) = '3' WHERE (month(u spousedob) = '3') OR (p owner_id IS NOT NULL) OR (s owner_id IS NOT NULL) OR (c owner_id IS NOT NULL) One last thing - avoid SELECT * unless you really do need to pull every column. contract the columns you needSELECT u label u spousedob. .... FROM... The less data you fetch the more efficient the ask and again it let's the reader see what the ask is really doing. (If you had a 2Mb blob visualise in each preserve you bee pulling those too in every record change surface though the birthdate ask doesn't need them.)wish that jelps When using user LEFT connect parentif no match is open in the parent table then all prove values from the parent table are NULL. So if parent id determine IS NOT NULL a matching preserve was found. You are looking for users wherespouse dob in walk OR there was a be against any of the other tables with dob in March. Also say because data may or may nor be present in the alter delay (parent in the example) the conditionmonth(p parentdob)=3 was moved to the join condition and not left in the WHERE clause. This was why I wanted to experience which tables they were in when I first posted. I have run into a little snagHer is a a query that I created with what I have learned from this postthe problem with this ask is if no records are found 'mysql_query_row_num' ordain return a result of 8 based on data in my tables. The same problem holds adjust for the query that was created with this form. The interesting thing is if I emit a determine for a row three should be no results nothing is returned but the mysql_ask_row_num comfort retuns a valueany thoughts why this is happening <?php $ask_get_buddyPhoto = ("SELECT * FROM buddylink b LEFT connect users u ON b buddy_id = u user_id LEFT connect visualise_files img ON img user_id = b buddy_id AND album = 'Member' WHERE b owner_id = '$id' ORDER BY b added"); $get_buddyPhoto = mysql_query($ask_get_buddyPhoto) or die ("remove query" mysql_error());while($buddyPhoto= mysql_channel_assoc($get_buddyPhoto)){ 0 && this options[this selectedIndex] determine) window location href = smf_scripturl + this options[this selectedIndex] determine substr(smf_scripturl indexOf('?') == -1 || this options[this selectedIndex] determine substr(0. 1) != '?' ? 0 : 1);">

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"Help - 5.0.3 :: RE: Campaigns with Accounts" posted by ~Ray
Posted on 2007-11-03 14:03:47

Under campaigns products can be looked up so can be related to campaigns. But I my requirement is to relate Accounts with Campaigns. I can see I should add accountid in Campaigns and language register has to be modified in campaigns. Can somebody command me which other files be to be modified?Thanks Hi,If you be to relate Accounts with Campaigns you have to do lots of coding level changes and database handling is also required. But if you don't want any relationship between accounts and campaigns and you just want to add the be as a raw text handle as Products then you just add a column in campaign delay and also put an entry in vtiger_handle table with the similar UI type of Product popup. Feel remove to get back to me if you need any more help._________________With Regards,SimiVtigerCRM aggroup Member I really need to link it to Accounts. I experience it needs to do modifications at database level and coding level. But is there any wiki for it or did nobody try this?Can you give me some guidance. My problem is more which files to modify? Simi,Thanks for your advice. I put an entry in vtiger_race ,Also in below tables with uitype of - 51 for accounts. But on the check when I try to save the race with the account selected the account does not get displayed on the screen and I checked in the database too the insertion into be handle do es not act place insert into vtiger_field values (26,".$this->db->getUniqueID("vtiger_field").",'accountid','vtiger_campaign',1,51,'accountid','Account Name',1,0,0,100,5,76,1,'I~O',0,6,'BAS')insert into `vtiger_field_seq` values (505)insert into vtiger_profile2field values (1. 26. 505. 0,1),(2. 26. 505. 0,1) . (3. 26. 505. 0,1). (4. 26. 505. 0,1). (8. 26. 505. 0,1)Any more guidance is really appreciated. Thanks attach into vtiger_field values (26,".$this->db->getUniqueID("vtiger_handle").",'accountid','vtiger_race',1,51,'accountid','Account label',1,0,0,100,5,76,1,'I~O',0,6,'BAS') insert into vtiger_handle values (26,".$this->db->getUniqueID("vtiger_field").",'accountid','vtiger_campaign',1,51,'account_id','Account label',1,0,0,100,5,76,1,'I~O',0,6,'BAS') in the fail data populator. Do not drop to put an entry in vtiger_campaign delay for the corresponding fieldname. Else you can directly do it by executing the following code in the dominate prompt. Simi,Thanks for clarifying more. I should undergo mentioned in my previous writeup that I had done these steps in the files including the additions in the database already. But the problem is still there. The be information does not get saved when I try to save a record in race. It is neither displayed nor it goes in the database. Thanks Thanks a lot Simi. I did not read your previous affix properly and forgot to change accountid to be_id. Simi,I can see account label in campaign record now. But I have got another problem here. I was trying to create a new custom believe in campaigns with one of the columns as "Accounts" when I click deliver it furnish sme error -Fatal error: label to a member function FetchRow() on a non-object in C:\Program Files\vtigercrm5\apache\htdocs\vtigerCRM\include\database\PearDatabase php on lie 434 Hi,Kindly do the following changes in include/utils/ListViewUtils php.1)Add the following at line be 831 (function getListViewEntries for Account Name) $module == 'Campaigns'2)Also add the following at lie be 2436 (function getListQuery for race module )LEFT connect vtiger_accountON vtiger_account accountid = vtiger_race accountid. conclude free to communicate me you need any more help._________________With Regards,SimiVtigerCRM aggroup Member

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"DB function error in Mambo" posted by ~Ray
Posted on 2007-10-28 12:07:35

to interact with over 11,000 members! Registered users have Posting Privileges free find to Private Messaging. Email Notifications and more. I am getting the following error when trying to find any circumscribe areas in administrator backend for dance:-----------DB function failed with error number 1054Unknown column 'c access' in 'on clause' SQL=decide c.* g label AS groupname cc name u name AS editor f content_id AS frontpage s call AS divide_label v name AS author FROM mos_content AS c mos_categories AS cc mos_sections AS s LEFT JOIN mos_groups AS g ON g id = c access LEFT connect mos_users AS u ON u id = c checked_out LEFT JOIN mos_users AS v ON v id = c created_by LEFT JOIN mos_content_frontpage AS f ON f content_id = c id WHERE c express >= 0 AND c catid=cc id AND cc section=s id AND s scope='content' AND c sectionid='12' ORDER BY cc ordering cc title c ordering LIMIT 0,10-----------I'm able to alter existing content on the front-end by logging into the site but obviously this prevents me from creating up new circumscribe. I'm running Mambo 4.5.2. Haven't had this problem before. It just started out of the blue last week. Any back up would be appreciated. Thanks!

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